distinguish between benzaldehyde and benzophenone

(ii) Distinction between Benzaldehyde and Benzoic acid: Benzaldehyde has no alpha hydrogen atom. Answer: Question 68. (i) LiAlH4 (Lithium Aluminium Hydride) Benzaldehyde being an aldehyde (b) (i) Due to much stronger I-effect of F over Cl, the FCH2COO– ion is much more stable than ClCH2COO– ion and hence FCH2COOH is a stronger acid than ClCH2COOH. (a) (i) Because one of the – NH2 in semicarbazide is involved in the resonance with -CO-group. (b) Distinguish between: (i) Propanal and Propanone, (ii) Benzaldehyde and Acetophenone. Acids react with NaHCO3 to produce brisk effervescence due to the evolution of CO2 gas. (All India 2009) (a) (i) Hell-Volhard-Zelinsky reaction : Carboxylic acid reacts with chlorine or bromine in presence of small quantities of red phosphorous to give exclusively α-chloro or α-bromo acids. (i) De-carboxylation reaction (ii) Friedel-Crafts reaction Answer: Question 50. Delhi 2014) Answer: (ii) Aldol condensation: Those aldehydes and ketones with atleast one a-hydrogen atom condense together in presence of dil. (a) Write chemical equations to illustrate the following name bearing reactions : (b) An organic compound (A) which has characteristic odour, on treatment with NaOH forms two compounds (B) and (C). Identify the compounds ‘A’ and ‘B’ and explain the reactions involved. (Delhi 2016) Ethanal gives yellow crystal of iodoform while propanal does not respond to iodoform test. What is Penicillin 3. Furthermore, these compounds act by inhibiting transpeptidases (the enzyme that catalyzes the synthesis of peptidoglycan). Answer: Propanal is an aldehyde. Question 63. (b) How will you bring about the following conversions? It must be an aldehyde. Answer Save. Write the structure of p-methylbenzaldehyde. Thanks!! The reaction is known as decarboxylation. (i) Etard reaction (ii) Stephen reduction Overview and Key Difference 2. (i) CH3—CHO is more reactive than CH3COCH3 towards HCN. (b) Mechanism of esterification of carboxylic acids : Question 71. (i) Electrophilic substitution in benzoic acid takes place at meta position. (e) A and B are two functional isomers of compound C3H6O. (a) (i) 4-Methoxy benzoic acid < Benzoic acid < 4-Nitrobenzoic acid < 3, 4-Dinitrobenzoic acid. Question 27. (ii) Since it gives orange red ppt with 2, 4-DNP reagent Therefore it must be either aldehyde or a ketone. Answer: Question 24. of iodoform. (b) Compound C9H10O forms 2, 4-DNP derivative, so it contains a carbonyl group. (All India 2009) Answer: Question 2. Benzaldehyde to 3-Phenylpropan-l-ol 8. (iii) Cl-(CH2)4-Cl into hexan-1, 6-diamine? All India) (ii) Because -COOH group of carboxylic acids is capable to do intermolecular hydrogen bonding forming a dimer while alcohols, aldehydes and ketones can not. References: 1. (Comptt. (i) Benzoic acid and Phenol (ii) Propanal and Propanone. Skip. (b) (i) Propanone to Propane Aldehydes respond to Fehling's test, but ketones do not. (i) CH3COCH3, C6H5COCH3, CH3CHO (ii) Hell-Volhard-Zelinsky reaction : Carboxylic acid reacts with chlorine or bromine in presence of small quantities of red phosphorous to give exclusively a-chloro or a-bromo acids. (ii) Clemmensen reduction: The carbonyl group of aldehyde and ketones is reduced to CH, group on treatment with zinc amalgam and concentrated hydrochloric acid. Answer: (i) HCN (ii) H2N – OH (iii) CH3CHO in the presence of dilute NaOH (b) Give simple tests to distinguish the following pairs of compounds : Fungal hyphae […], The key difference between yeast and mucor is that yeast is a single-celled fungus and is non-mycelial, while mucor is a filamentous fungus, which is a form of mycelial. Acetophenone and Benzophenone 3. Answer: Henry's law constant for CO2 in water is 1.67 x 108Pa at 298 K. Calculate the quantity of CO2in 500 mL of soda water when packed under 2.5 atm CO2 pressure at 298 K. How the following conversions can be carried out? Deduce the structures of ‘A’, ‘B’, ‘C’ and ‘D’. (ii) Acetophenone and Benzophenone (d) Write the product in the following reaction (a) (i) Acetylation: The addition of acyl (-COCH3) group on the ortho and para positions of acyl halide in the presence of a Lewis acid i.e. Answer: Question 19. Delhi 2017) A 5% solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of 5% glucose in water if freezing point of pure water is 273.15 K. Calculate the mass of urea (NH2CONH2) required in making 2.5 kg of 0.25 molal aqueous solution. Example : (b) (i) Propanal and propanone: Propanal gives a positive test with the Fehling solution in which a red ppt. Give complete reaction in each case. (ii) Benzoic acid to m-nitrobenzyl alcohol : Delhi 2013) Question 77. (Comptt. Draw the structure of 3-methylbutanal. Write IUPAC name of the following : (Comptt. Compound ‘B’ has the molecular formula C7H8O which on oxidation with CrO3 gives back compound ‘A’. And, its melting point is -57.12 °C while the boiling point is 178.1 °C. Both aliphatic and aromatic aldehydes reduce Tollen’s reagent to shining silver mirror. reagent and undergoes Cannizzaro’s reaction. Calculate the mass of a non-volatile solute (molar mass 40 g mol-1) which should be dissolved in 114 g octane to reduce its vapour pressure to 80%. Delhi 2012) I appreciate it a ton!! (Comptt. (b) How would you bring about the following conversions : (a) Give chemical tests to distinguish between Question 12. (b) (i) Pollen’s reagent test. (All India 2011) (ii) Friedel-Crafts reaction: The introduction of alkyl or acetyl group in the presence of anhydrous almuninium chloride (AlCl3) as catalyst to ortho and para positions of an aromatic compound is called Friedel-Crafts reaction.

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